Physics Education

LESSON PLANE.

SCHOOL : SMA N 10 PADANG

CLASS : XI INTERNATIONAL

SUBJECT : PHYSICS

TOPICS : THERMODYNAMIC

STANDARD COMPETENCE : To Apply the concept of Thermodynamics in heat mechine

BASIC COMPETENCE : To analyze the changing varables of ideal gas by applicating the law of thermodynamics..

INDICATORS for studying:

a. By repeating the result of model theory Kinetic’s experiment the student be able to

Recall the relationship between Energy kinetics and temperature in equipartisie Energy of particle. ,
Formulate the Inners energy in gas.
recall the relationship between Pressure ( P ) and Volume ( V ),Temperature and n ( mole gas )

b. by using presentation power point which gas give a heat student be able to

1. . analyze the work which is gas doing in variable conditions of gas .

Formulate the first law of Thermodynamics.
analyze the first law of thermodunamic in variable conditions of gas

c. by using diagram Carnot machine the student can be able to describe the relationship between heat absorptions ,work and heat releasing .and describe the maximum efficiency of Carnot machine

d. by using diagram of Refrigerator machine the student can be able to describe the relationship between heat absorptions ,work and heat releasing .and describe the maximum efficiency of machine ..

ESSENTIAL MATTERS:

Gas always move with Brown Motion except O^o K.it is called Absolute zero temperature and each direction has kinetic Energy = ½ kT ( k=bolztman constant , T=temperature in Kelvin.) statement of Maxwel.

So the Kinetic’s Energy of ideal gas = 3/2 n R T

If one direction of motions the kinetic’s energy is ½ kt the kinetic’s energy total for :

Helium gas in lower temperature = 3/2 kT

medium temperature = 3/2 kT

higher temperature = 3/2 kT.

So Mono atomic gas just only move with three direction of translations

Oksigen gas in lower temperature = 3/2 kt

medium temperature = 3/2 kT + 2/2 kT = 5/2 kT

higher temperature = 3/2 kt + 2/2 kT + 2/2 kT = 7/2 kT

Ozon Gas . in lower temperature = 3/2 kT

medium temperature =3/2 kT + 3 x 2/2 kT = 9/2 kT

higher temperature =3/2 kT + 3x 2/2 kT +3x 2/2 kT = 15/2 kT

So Ideal Gas is all gasses in lower temperature it has kinetic’s energy = 3/2 kT for one molekul but in tube there are N molecules Ek = 3/2 N k T = 3/2 n R T.

We have found the equation if ideal gas like the equations below :

P.V = n R T ( Boyle Gay Lussac )

EXTERNAL WORK :

External Work = W = P.∆V = P ( V₂ – V₁ ) for pressure constant

If the pressure is changing the work can find by calculating the area of P-V diagram.

There are four process in thermodynamic :

Isobaric Process:

P W = P ( V₂ – V₁ )

0 V₁ V₂

Isochoric Process : Vokume is constant so W = zero = 0

Isotermic Process : Pascal

It can be calculate ~ area of trapezium

P₁ = 4 dW = P dV

dW = nRT/V dV

∫dW = nRT ∫V^-1 dV

P2 = 1 W = nRT ( ln V₂ – ln V₁ )

W = P₁V₁ ( ln V₂ – ln V₁ )

0 1 2 3 4

Adiabatic Process : P₁.V₁^γ = P_2.V₂^γ γ = laplace’s constant = 1,3

For finding this work just to make grap and calculate the area of P-V.

Thermodynamic’s Law :

ACTIVITY:

Preface : The teacher thanks to God , and then ask the chairman to pray to God 5’

Using Computer for showing the Topics and Indicators. 5’

Action : Informasi About Kinetics Theory Model and principle of Equiparticy 15’

Energy of gas .

Till find the equation of velocity.

Ask Danu to take place in front of the class for lead the practicer 5’

And group A will do the experiment no 1,2,3, and one of the member in 15’ group writte the result on the stricker and put it on the board and talking about the conclusion .

So follow with group B and C and Danu still the leader for practice 30’

One of them make all conclusion for formulate the relationship among 15’ P.V.T and n,R

Checlist:Ask the student for describe what has they found in this activity. 10’

Exercise with 2 problem 20’

120’

Problem :

1. Soal fisika UMPTN 99 Rayon B No. 27

B A

3N` N

300 K

volume B = 2 x volume tabung A, both containing gas ideal.The volume of tube that connect A to B is smallaest equal zero. Gass A has temperature 300 K.total molecul in A = N and in B = 3 N, so the temperature B is;

(A). 150 K (B). 200 K (C). 300 K (D). 450 K (E). 600 K

2. A container hold gas at 27^oC To what temperature must it be heated for the pressure to double ? Assume the volume of the gas remains unchanged .

Signature ,Head Master Padang,22 February 2008

Physics teacher.

Drs.H.Safarni Budaya Putra Desmalinda

Nip : 130 784 576 Nip : 132 169 759